Initial checkin from CRI-O repo

Signed-off-by: Matthew Heon <matthew.heon@gmail.com>

1 files changed, 594 insertions, 0 deletions

diff --git a/vendor/github.com/tchap/go-patricia/patricia/patricia.go b/vendor/github.com/tchap/go-patricia/patricia/patricia.go
new file mode 100644
index 000000000..a1fc53d5d
--- /dev/null
+++ b/vendor/github.com/tchap/go-patricia/patricia/patricia.go
@@ -0,0 +1,594 @@
+// Copyright (c) 2014 The go-patricia AUTHORS
+//
+// Use of this source code is governed by The MIT License
+// that can be found in the LICENSE file.
+
+package patricia
+
+import (
+	"bytes"
+	"errors"
+	"fmt"
+	"io"
+	"strings"
+)
+
+//------------------------------------------------------------------------------
+// Trie
+//------------------------------------------------------------------------------
+
+const (
+	DefaultMaxPrefixPerNode         = 10
+	DefaultMaxChildrenPerSparseNode = 8
+)
+
+type (
+	Prefix      []byte
+	Item        interface{}
+	VisitorFunc func(prefix Prefix, item Item) error
+)
+
+// Trie is a generic patricia trie that allows fast retrieval of items by prefix.
+// and other funky stuff.
+//
+// Trie is not thread-safe.
+type Trie struct {
+	prefix Prefix
+	item   Item
+
+	maxPrefixPerNode         int
+	maxChildrenPerSparseNode int
+
+	children childList
+}
+
+// Public API ------------------------------------------------------------------
+
+type Option func(*Trie)
+
+// Trie constructor.
+func NewTrie(options ...Option) *Trie {
+	trie := &Trie{}
+
+	for _, opt := range options {
+		opt(trie)
+	}
+
+	if trie.maxPrefixPerNode <= 0 {
+		trie.maxPrefixPerNode = DefaultMaxPrefixPerNode
+	}
+	if trie.maxChildrenPerSparseNode <= 0 {
+		trie.maxChildrenPerSparseNode = DefaultMaxChildrenPerSparseNode
+	}
+
+	trie.children = newSparseChildList(trie.maxChildrenPerSparseNode)
+	return trie
+}
+
+func MaxPrefixPerNode(value int) Option {
+	return func(trie *Trie) {
+		trie.maxPrefixPerNode = value
+	}
+}
+
+func MaxChildrenPerSparseNode(value int) Option {
+	return func(trie *Trie) {
+		trie.maxChildrenPerSparseNode = value
+	}
+}
+
+// Item returns the item stored in the root of this trie.
+func (trie *Trie) Item() Item {
+	return trie.item
+}
+
+// Insert inserts a new item into the trie using the given prefix. Insert does
+// not replace existing items. It returns false if an item was already in place.
+func (trie *Trie) Insert(key Prefix, item Item) (inserted bool) {
+	return trie.put(key, item, false)
+}
+
+// Set works much like Insert, but it always sets the item, possibly replacing
+// the item previously inserted.
+func (trie *Trie) Set(key Prefix, item Item) {
+	trie.put(key, item, true)
+}
+
+// Get returns the item located at key.
+//
+// This method is a bit dangerous, because Get can as well end up in an internal
+// node that is not really representing any user-defined value. So when nil is
+// a valid value being used, it is not possible to tell if the value was inserted
+// into the tree by the user or not. A possible workaround for this is not to use
+// nil interface as a valid value, even using zero value of any type is enough
+// to prevent this bad behaviour.
+func (trie *Trie) Get(key Prefix) (item Item) {
+	_, node, found, leftover := trie.findSubtree(key)
+	if !found || len(leftover) != 0 {
+		return nil
+	}
+	return node.item
+}
+
+// Match returns what Get(prefix) != nil would return. The same warning as for
+// Get applies here as well.
+func (trie *Trie) Match(prefix Prefix) (matchedExactly bool) {
+	return trie.Get(prefix) != nil
+}
+
+// MatchSubtree returns true when there is a subtree representing extensions
+// to key, that is if there are any keys in the tree which have key as prefix.
+func (trie *Trie) MatchSubtree(key Prefix) (matched bool) {
+	_, _, matched, _ = trie.findSubtree(key)
+	return
+}
+
+// Visit calls visitor on every node containing a non-nil item
+// in alphabetical order.
+//
+// If an error is returned from visitor, the function stops visiting the tree
+// and returns that error, unless it is a special error - SkipSubtree. In that
+// case Visit skips the subtree represented by the current node and continues
+// elsewhere.
+func (trie *Trie) Visit(visitor VisitorFunc) error {
+	return trie.walk(nil, visitor)
+}
+
+func (trie *Trie) size() int {
+	n := 0
+
+	trie.walk(nil, func(prefix Prefix, item Item) error {
+		n++
+		return nil
+	})
+
+	return n
+}
+
+func (trie *Trie) total() int {
+	return 1 + trie.children.total()
+}
+
+// VisitSubtree works much like Visit, but it only visits nodes matching prefix.
+func (trie *Trie) VisitSubtree(prefix Prefix, visitor VisitorFunc) error {
+	// Nil prefix not allowed.
+	if prefix == nil {
+		panic(ErrNilPrefix)
+	}
+
+	// Empty trie must be handled explicitly.
+	if trie.prefix == nil {
+		return nil
+	}
+
+	// Locate the relevant subtree.
+	_, root, found, leftover := trie.findSubtree(prefix)
+	if !found {
+		return nil
+	}
+	prefix = append(prefix, leftover...)
+
+	// Visit it.
+	return root.walk(prefix, visitor)
+}
+
+// VisitPrefixes visits only nodes that represent prefixes of key.
+// To say the obvious, returning SkipSubtree from visitor makes no sense here.
+func (trie *Trie) VisitPrefixes(key Prefix, visitor VisitorFunc) error {
+	// Nil key not allowed.
+	if key == nil {
+		panic(ErrNilPrefix)
+	}
+
+	// Empty trie must be handled explicitly.
+	if trie.prefix == nil {
+		return nil
+	}
+
+	// Walk the path matching key prefixes.
+	node := trie
+	prefix := key
+	offset := 0
+	for {
+		// Compute what part of prefix matches.
+		common := node.longestCommonPrefixLength(key)
+		key = key[common:]
+		offset += common
+
+		// Partial match means that there is no subtree matching prefix.
+		if common < len(node.prefix) {
+			return nil
+		}
+
+		// Call the visitor.
+		if item := node.item; item != nil {
+			if err := visitor(prefix[:offset], item); err != nil {
+				return err
+			}
+		}
+
+		if len(key) == 0 {
+			// This node represents key, we are finished.
+			return nil
+		}
+
+		// There is some key suffix left, move to the children.
+		child := node.children.next(key[0])
+		if child == nil {
+			// There is nowhere to continue, return.
+			return nil
+		}
+
+		node = child
+	}
+}
+
+// Delete deletes the item represented by the given prefix.
+//
+// True is returned if the matching node was found and deleted.
+func (trie *Trie) Delete(key Prefix) (deleted bool) {
+	// Nil prefix not allowed.
+	if key == nil {
+		panic(ErrNilPrefix)
+	}
+
+	// Empty trie must be handled explicitly.
+	if trie.prefix == nil {
+		return false
+	}
+
+	// Find the relevant node.
+	path, found, _ := trie.findSubtreePath(key)
+	if !found {
+		return false
+	}
+
+	node := path[len(path)-1]
+	var parent *Trie
+	if len(path) != 1 {
+		parent = path[len(path)-2]
+	}
+
+	// If the item is already set to nil, there is nothing to do.
+	if node.item == nil {
+		return false
+	}
+
+	// Delete the item.
+	node.item = nil
+
+	// Initialise i before goto.
+	// Will be used later in a loop.
+	i := len(path) - 1
+
+	// In case there are some child nodes, we cannot drop the whole subtree.
+	// We can try to compact nodes, though.
+	if node.children.length() != 0 {
+		goto Compact
+	}
+
+	// In case we are at the root, just reset it and we are done.
+	if parent == nil {
+		node.reset()
+		return true
+	}
+
+	// We can drop a subtree.
+	// Find the first ancestor that has its value set or it has 2 or more child nodes.
+	// That will be the node where to drop the subtree at.
+	for ; i >= 0; i-- {
+		if current := path[i]; current.item != nil || current.children.length() >= 2 {
+			break
+		}
+	}
+
+	// Handle the case when there is no such node.
+	// In other words, we can reset the whole tree.
+	if i == -1 {
+		path[0].reset()
+		return true
+	}
+
+	// We can just remove the subtree here.
+	node = path[i]
+	if i == 0 {
+		parent = nil
+	} else {
+		parent = path[i-1]
+	}
+	// i+1 is always a valid index since i is never pointing to the last node.
+	// The loop above skips at least the last node since we are sure that the item
+	// is set to nil and it has no children, othewise we would be compacting instead.
+	node.children.remove(path[i+1].prefix[0])
+
+Compact:
+	// The node is set to the first non-empty ancestor,
+	// so try to compact since that might be possible now.
+	if compacted := node.compact(); compacted != node {
+		if parent == nil {
+			*node = *compacted
+		} else {
+			parent.children.replace(node.prefix[0], compacted)
+			*parent = *parent.compact()
+		}
+	}
+
+	return true
+}
+
+// DeleteSubtree finds the subtree exactly matching prefix and deletes it.
+//
+// True is returned if the subtree was found and deleted.
+func (trie *Trie) DeleteSubtree(prefix Prefix) (deleted bool) {
+	// Nil prefix not allowed.
+	if prefix == nil {
+		panic(ErrNilPrefix)
+	}
+
+	// Empty trie must be handled explicitly.
+	if trie.prefix == nil {
+		return false
+	}
+
+	// Locate the relevant subtree.
+	parent, root, found, _ := trie.findSubtree(prefix)
+	if !found {
+		return false
+	}
+
+	// If we are in the root of the trie, reset the trie.
+	if parent == nil {
+		root.reset()
+		return true
+	}
+
+	// Otherwise remove the root node from its parent.
+	parent.children.remove(root.prefix[0])
+	return true
+}
+
+// Internal helper methods -----------------------------------------------------
+
+func (trie *Trie) empty() bool {
+	return trie.item == nil && trie.children.length() == 0
+}
+
+func (trie *Trie) reset() {
+	trie.prefix = nil
+	trie.children = newSparseChildList(trie.maxPrefixPerNode)
+}
+
+func (trie *Trie) put(key Prefix, item Item, replace bool) (inserted bool) {
+	// Nil prefix not allowed.
+	if key == nil {
+		panic(ErrNilPrefix)
+	}
+
+	var (
+		common int
+		node   *Trie = trie
+		child  *Trie
+	)
+
+	if node.prefix == nil {
+		if len(key) <= trie.maxPrefixPerNode {
+			node.prefix = key
+			goto InsertItem
+		}
+		node.prefix = key[:trie.maxPrefixPerNode]
+		key = key[trie.maxPrefixPerNode:]
+		goto AppendChild
+	}
+
+	for {
+		// Compute the longest common prefix length.
+		common = node.longestCommonPrefixLength(key)
+		key = key[common:]
+
+		// Only a part matches, split.
+		if common < len(node.prefix) {
+			goto SplitPrefix
+		}
+
+		// common == len(node.prefix) since never (common > len(node.prefix))
+		// common == len(former key) <-> 0 == len(key)
+		// -> former key == node.prefix
+		if len(key) == 0 {
+			goto InsertItem
+		}
+
+		// Check children for matching prefix.
+		child = node.children.next(key[0])
+		if child == nil {
+			goto AppendChild
+		}
+		node = child
+	}
+
+SplitPrefix:
+	// Split the prefix if necessary.
+	child = new(Trie)
+	*child = *node
+	*node = *NewTrie()
+	node.prefix = child.prefix[:common]
+	child.prefix = child.prefix[common:]
+	child = child.compact()
+	node.children = node.children.add(child)
+
+AppendChild:
+	// Keep appending children until whole prefix is inserted.
+	// This loop starts with empty node.prefix that needs to be filled.
+	for len(key) != 0 {
+		child := NewTrie()
+		if len(key) <= trie.maxPrefixPerNode {
+			child.prefix = key
+			node.children = node.children.add(child)
+			node = child
+			goto InsertItem
+		} else {
+			child.prefix = key[:trie.maxPrefixPerNode]
+			key = key[trie.maxPrefixPerNode:]
+			node.children = node.children.add(child)
+			node = child
+		}
+	}
+
+InsertItem:
+	// Try to insert the item if possible.
+	if replace || node.item == nil {
+		node.item = item
+		return true
+	}
+	return false
+}
+
+func (trie *Trie) compact() *Trie {
+	// Only a node with a single child can be compacted.
+	if trie.children.length() != 1 {
+		return trie
+	}
+
+	child := trie.children.head()
+
+	// If any item is set, we cannot compact since we want to retain
+	// the ability to do searching by key. This makes compaction less usable,
+	// but that simply cannot be avoided.
+	if trie.item != nil || child.item != nil {
+		return trie
+	}
+
+	// Make sure the combined prefixes fit into a single node.
+	if len(trie.prefix)+len(child.prefix) > trie.maxPrefixPerNode {
+		return trie
+	}
+
+	// Concatenate the prefixes, move the items.
+	child.prefix = append(trie.prefix, child.prefix...)
+	if trie.item != nil {
+		child.item = trie.item
+	}
+
+	return child
+}
+
+func (trie *Trie) findSubtree(prefix Prefix) (parent *Trie, root *Trie, found bool, leftover Prefix) {
+	// Find the subtree matching prefix.
+	root = trie
+	for {
+		// Compute what part of prefix matches.
+		common := root.longestCommonPrefixLength(prefix)
+		prefix = prefix[common:]
+
+		// We used up the whole prefix, subtree found.
+		if len(prefix) == 0 {
+			found = true
+			leftover = root.prefix[common:]
+			return
+		}
+
+		// Partial match means that there is no subtree matching prefix.
+		if common < len(root.prefix) {
+			leftover = root.prefix[common:]
+			return
+		}
+
+		// There is some prefix left, move to the children.
+		child := root.children.next(prefix[0])
+		if child == nil {
+			// There is nowhere to continue, there is no subtree matching prefix.
+			return
+		}
+
+		parent = root
+		root = child
+	}
+}
+
+func (trie *Trie) findSubtreePath(prefix Prefix) (path []*Trie, found bool, leftover Prefix) {
+	// Find the subtree matching prefix.
+	root := trie
+	var subtreePath []*Trie
+	for {
+		// Append the current root to the path.
+		subtreePath = append(subtreePath, root)
+
+		// Compute what part of prefix matches.
+		common := root.longestCommonPrefixLength(prefix)
+		prefix = prefix[common:]
+
+		// We used up the whole prefix, subtree found.
+		if len(prefix) == 0 {
+			path = subtreePath
+			found = true
+			leftover = root.prefix[common:]
+			return
+		}
+
+		// Partial match means that there is no subtree matching prefix.
+		if common < len(root.prefix) {
+			leftover = root.prefix[common:]
+			return
+		}
+
+		// There is some prefix left, move to the children.
+		child := root.children.next(prefix[0])
+		if child == nil {
+			// There is nowhere to continue, there is no subtree matching prefix.
+			return
+		}
+
+		root = child
+	}
+}
+
+func (trie *Trie) walk(actualRootPrefix Prefix, visitor VisitorFunc) error {
+	var prefix Prefix
+	// Allocate a bit more space for prefix at the beginning.
+	if actualRootPrefix == nil {
+		prefix = make(Prefix, 32+len(trie.prefix))
+		copy(prefix, trie.prefix)
+		prefix = prefix[:len(trie.prefix)]
+	} else {
+		prefix = make(Prefix, 32+len(actualRootPrefix))
+		copy(prefix, actualRootPrefix)
+		prefix = prefix[:len(actualRootPrefix)]
+	}
+
+	// Visit the root first. Not that this works for empty trie as well since
+	// in that case item == nil && len(children) == 0.
+	if trie.item != nil {
+		if err := visitor(prefix, trie.item); err != nil {
+			if err == SkipSubtree {
+				return nil
+			}
+			return err
+		}
+	}
+
+	// Then continue to the children.
+	return trie.children.walk(&prefix, visitor)
+}
+
+func (trie *Trie) longestCommonPrefixLength(prefix Prefix) (i int) {
+	for ; i < len(prefix) && i < len(trie.prefix) && prefix[i] == trie.prefix[i]; i++ {
+	}
+	return
+}
+
+func (trie *Trie) dump() string {
+	writer := &bytes.Buffer{}
+	trie.print(writer, 0)
+	return writer.String()
+}
+
+func (trie *Trie) print(writer io.Writer, indent int) {
+	fmt.Fprintf(writer, "%s%s %v\n", strings.Repeat(" ", indent), string(trie.prefix), trie.item)
+	trie.children.print(writer, indent+2)
+}
+
+// Errors ----------------------------------------------------------------------
+
+var (
+	SkipSubtree  = errors.New("Skip this subtree")
+	ErrNilPrefix = errors.New("Nil prefix passed into a method call")
+)