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-rw-r--r--vendor/github.com/klauspost/compress/flate/huffman_code.go344
1 files changed, 344 insertions, 0 deletions
diff --git a/vendor/github.com/klauspost/compress/flate/huffman_code.go b/vendor/github.com/klauspost/compress/flate/huffman_code.go
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index 000000000..bdcbd823b
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+++ b/vendor/github.com/klauspost/compress/flate/huffman_code.go
@@ -0,0 +1,344 @@
+// Copyright 2009 The Go Authors. All rights reserved.
+// Use of this source code is governed by a BSD-style
+// license that can be found in the LICENSE file.
+
+package flate
+
+import (
+ "math"
+ "sort"
+)
+
+// hcode is a huffman code with a bit code and bit length.
+type hcode struct {
+ code, len uint16
+}
+
+type huffmanEncoder struct {
+ codes []hcode
+ freqcache []literalNode
+ bitCount [17]int32
+ lns byLiteral // stored to avoid repeated allocation in generate
+ lfs byFreq // stored to avoid repeated allocation in generate
+}
+
+type literalNode struct {
+ literal uint16
+ freq int32
+}
+
+// A levelInfo describes the state of the constructed tree for a given depth.
+type levelInfo struct {
+ // Our level. for better printing
+ level int32
+
+ // The frequency of the last node at this level
+ lastFreq int32
+
+ // The frequency of the next character to add to this level
+ nextCharFreq int32
+
+ // The frequency of the next pair (from level below) to add to this level.
+ // Only valid if the "needed" value of the next lower level is 0.
+ nextPairFreq int32
+
+ // The number of chains remaining to generate for this level before moving
+ // up to the next level
+ needed int32
+}
+
+// set sets the code and length of an hcode.
+func (h *hcode) set(code uint16, length uint16) {
+ h.len = length
+ h.code = code
+}
+
+func maxNode() literalNode { return literalNode{math.MaxUint16, math.MaxInt32} }
+
+func newHuffmanEncoder(size int) *huffmanEncoder {
+ return &huffmanEncoder{codes: make([]hcode, size)}
+}
+
+// Generates a HuffmanCode corresponding to the fixed literal table
+func generateFixedLiteralEncoding() *huffmanEncoder {
+ h := newHuffmanEncoder(maxNumLit)
+ codes := h.codes
+ var ch uint16
+ for ch = 0; ch < maxNumLit; ch++ {
+ var bits uint16
+ var size uint16
+ switch {
+ case ch < 144:
+ // size 8, 000110000 .. 10111111
+ bits = ch + 48
+ size = 8
+ break
+ case ch < 256:
+ // size 9, 110010000 .. 111111111
+ bits = ch + 400 - 144
+ size = 9
+ break
+ case ch < 280:
+ // size 7, 0000000 .. 0010111
+ bits = ch - 256
+ size = 7
+ break
+ default:
+ // size 8, 11000000 .. 11000111
+ bits = ch + 192 - 280
+ size = 8
+ }
+ codes[ch] = hcode{code: reverseBits(bits, byte(size)), len: size}
+ }
+ return h
+}
+
+func generateFixedOffsetEncoding() *huffmanEncoder {
+ h := newHuffmanEncoder(30)
+ codes := h.codes
+ for ch := range codes {
+ codes[ch] = hcode{code: reverseBits(uint16(ch), 5), len: 5}
+ }
+ return h
+}
+
+var fixedLiteralEncoding *huffmanEncoder = generateFixedLiteralEncoding()
+var fixedOffsetEncoding *huffmanEncoder = generateFixedOffsetEncoding()
+
+func (h *huffmanEncoder) bitLength(freq []int32) int {
+ var total int
+ for i, f := range freq {
+ if f != 0 {
+ total += int(f) * int(h.codes[i].len)
+ }
+ }
+ return total
+}
+
+const maxBitsLimit = 16
+
+// Return the number of literals assigned to each bit size in the Huffman encoding
+//
+// This method is only called when list.length >= 3
+// The cases of 0, 1, and 2 literals are handled by special case code.
+//
+// list An array of the literals with non-zero frequencies
+// and their associated frequencies. The array is in order of increasing
+// frequency, and has as its last element a special element with frequency
+// MaxInt32
+// maxBits The maximum number of bits that should be used to encode any literal.
+// Must be less than 16.
+// return An integer array in which array[i] indicates the number of literals
+// that should be encoded in i bits.
+func (h *huffmanEncoder) bitCounts(list []literalNode, maxBits int32) []int32 {
+ if maxBits >= maxBitsLimit {
+ panic("flate: maxBits too large")
+ }
+ n := int32(len(list))
+ list = list[0 : n+1]
+ list[n] = maxNode()
+
+ // The tree can't have greater depth than n - 1, no matter what. This
+ // saves a little bit of work in some small cases
+ if maxBits > n-1 {
+ maxBits = n - 1
+ }
+
+ // Create information about each of the levels.
+ // A bogus "Level 0" whose sole purpose is so that
+ // level1.prev.needed==0. This makes level1.nextPairFreq
+ // be a legitimate value that never gets chosen.
+ var levels [maxBitsLimit]levelInfo
+ // leafCounts[i] counts the number of literals at the left
+ // of ancestors of the rightmost node at level i.
+ // leafCounts[i][j] is the number of literals at the left
+ // of the level j ancestor.
+ var leafCounts [maxBitsLimit][maxBitsLimit]int32
+
+ for level := int32(1); level <= maxBits; level++ {
+ // For every level, the first two items are the first two characters.
+ // We initialize the levels as if we had already figured this out.
+ levels[level] = levelInfo{
+ level: level,
+ lastFreq: list[1].freq,
+ nextCharFreq: list[2].freq,
+ nextPairFreq: list[0].freq + list[1].freq,
+ }
+ leafCounts[level][level] = 2
+ if level == 1 {
+ levels[level].nextPairFreq = math.MaxInt32
+ }
+ }
+
+ // We need a total of 2*n - 2 items at top level and have already generated 2.
+ levels[maxBits].needed = 2*n - 4
+
+ level := maxBits
+ for {
+ l := &levels[level]
+ if l.nextPairFreq == math.MaxInt32 && l.nextCharFreq == math.MaxInt32 {
+ // We've run out of both leafs and pairs.
+ // End all calculations for this level.
+ // To make sure we never come back to this level or any lower level,
+ // set nextPairFreq impossibly large.
+ l.needed = 0
+ levels[level+1].nextPairFreq = math.MaxInt32
+ level++
+ continue
+ }
+
+ prevFreq := l.lastFreq
+ if l.nextCharFreq < l.nextPairFreq {
+ // The next item on this row is a leaf node.
+ n := leafCounts[level][level] + 1
+ l.lastFreq = l.nextCharFreq
+ // Lower leafCounts are the same of the previous node.
+ leafCounts[level][level] = n
+ l.nextCharFreq = list[n].freq
+ } else {
+ // The next item on this row is a pair from the previous row.
+ // nextPairFreq isn't valid until we generate two
+ // more values in the level below
+ l.lastFreq = l.nextPairFreq
+ // Take leaf counts from the lower level, except counts[level] remains the same.
+ copy(leafCounts[level][:level], leafCounts[level-1][:level])
+ levels[l.level-1].needed = 2
+ }
+
+ if l.needed--; l.needed == 0 {
+ // We've done everything we need to do for this level.
+ // Continue calculating one level up. Fill in nextPairFreq
+ // of that level with the sum of the two nodes we've just calculated on
+ // this level.
+ if l.level == maxBits {
+ // All done!
+ break
+ }
+ levels[l.level+1].nextPairFreq = prevFreq + l.lastFreq
+ level++
+ } else {
+ // If we stole from below, move down temporarily to replenish it.
+ for levels[level-1].needed > 0 {
+ level--
+ }
+ }
+ }
+
+ // Somethings is wrong if at the end, the top level is null or hasn't used
+ // all of the leaves.
+ if leafCounts[maxBits][maxBits] != n {
+ panic("leafCounts[maxBits][maxBits] != n")
+ }
+
+ bitCount := h.bitCount[:maxBits+1]
+ bits := 1
+ counts := &leafCounts[maxBits]
+ for level := maxBits; level > 0; level-- {
+ // chain.leafCount gives the number of literals requiring at least "bits"
+ // bits to encode.
+ bitCount[bits] = counts[level] - counts[level-1]
+ bits++
+ }
+ return bitCount
+}
+
+// Look at the leaves and assign them a bit count and an encoding as specified
+// in RFC 1951 3.2.2
+func (h *huffmanEncoder) assignEncodingAndSize(bitCount []int32, list []literalNode) {
+ code := uint16(0)
+ for n, bits := range bitCount {
+ code <<= 1
+ if n == 0 || bits == 0 {
+ continue
+ }
+ // The literals list[len(list)-bits] .. list[len(list)-bits]
+ // are encoded using "bits" bits, and get the values
+ // code, code + 1, .... The code values are
+ // assigned in literal order (not frequency order).
+ chunk := list[len(list)-int(bits):]
+
+ h.lns.sort(chunk)
+ for _, node := range chunk {
+ h.codes[node.literal] = hcode{code: reverseBits(code, uint8(n)), len: uint16(n)}
+ code++
+ }
+ list = list[0 : len(list)-int(bits)]
+ }
+}
+
+// Update this Huffman Code object to be the minimum code for the specified frequency count.
+//
+// freq An array of frequencies, in which frequency[i] gives the frequency of literal i.
+// maxBits The maximum number of bits to use for any literal.
+func (h *huffmanEncoder) generate(freq []int32, maxBits int32) {
+ if h.freqcache == nil {
+ // Allocate a reusable buffer with the longest possible frequency table.
+ // Possible lengths are codegenCodeCount, offsetCodeCount and maxNumLit.
+ // The largest of these is maxNumLit, so we allocate for that case.
+ h.freqcache = make([]literalNode, maxNumLit+1)
+ }
+ list := h.freqcache[:len(freq)+1]
+ // Number of non-zero literals
+ count := 0
+ // Set list to be the set of all non-zero literals and their frequencies
+ for i, f := range freq {
+ if f != 0 {
+ list[count] = literalNode{uint16(i), f}
+ count++
+ } else {
+ list[count] = literalNode{}
+ h.codes[i].len = 0
+ }
+ }
+ list[len(freq)] = literalNode{}
+
+ list = list[:count]
+ if count <= 2 {
+ // Handle the small cases here, because they are awkward for the general case code. With
+ // two or fewer literals, everything has bit length 1.
+ for i, node := range list {
+ // "list" is in order of increasing literal value.
+ h.codes[node.literal].set(uint16(i), 1)
+ }
+ return
+ }
+ h.lfs.sort(list)
+
+ // Get the number of literals for each bit count
+ bitCount := h.bitCounts(list, maxBits)
+ // And do the assignment
+ h.assignEncodingAndSize(bitCount, list)
+}
+
+type byLiteral []literalNode
+
+func (s *byLiteral) sort(a []literalNode) {
+ *s = byLiteral(a)
+ sort.Sort(s)
+}
+
+func (s byLiteral) Len() int { return len(s) }
+
+func (s byLiteral) Less(i, j int) bool {
+ return s[i].literal < s[j].literal
+}
+
+func (s byLiteral) Swap(i, j int) { s[i], s[j] = s[j], s[i] }
+
+type byFreq []literalNode
+
+func (s *byFreq) sort(a []literalNode) {
+ *s = byFreq(a)
+ sort.Sort(s)
+}
+
+func (s byFreq) Len() int { return len(s) }
+
+func (s byFreq) Less(i, j int) bool {
+ if s[i].freq == s[j].freq {
+ return s[i].literal < s[j].literal
+ }
+ return s[i].freq < s[j].freq
+}
+
+func (s byFreq) Swap(i, j int) { s[i], s[j] = s[j], s[i] }