--- title: String.prototype.substring() slug: Web/JavaScript/Reference/Global_Objects/String/substring translation_of: Web/JavaScript/Reference/Global_Objects/String/substring ---
substring()
메소드는 string 객체의 시작 인덱스로 부터 종료 인덱스 전 까지 문자열의 부분 문자열을 반환합니다.
str.substring(indexStart[, indexEnd])
indexStart
indexEnd
기존문자열의 부분 문자열을 반환합니다.
substring()
메서드는 indexStart
부터 문자를 추출하지만 indexEnd
가 포함되지 않아도 괜찮습니다. 특징은 아래와 같습니다.
indexEnd
가 생략된 경우, substring()
문자열의 끝까지 모든 문자를 추출합니다.indexStart
가 indexEnd
와 같을 경우, substring()
빈 문자열을 반환합니다.indexStart
가 indexEnd
보다 큰 경우, substring()
메서드는 마치 두 개의 인자를 바꾼 듯 작동하게 됩니다. 아래 예제를 보세요.0보다 작은 인자 값을 가지는 경우에는 0으로, stringName.length
보다 큰 인자 값을 가지는 경우, stringName.length
로 처리됩니다. {{jsxref("NaN")}} 값은 0으로 처리됩니다.
substring()
The following example uses substring()
to display characters from the string 'Mozilla'
:
var anyString = 'Mozilla'; // Displays 'M' console.log(anyString.substring(0, 1)); console.log(anyString.substring(1, 0)); // Displays 'Mozill' console.log(anyString.substring(0, 6)); // Displays 'lla' console.log(anyString.substring(4)); console.log(anyString.substring(4, 7)); console.log(anyString.substring(7, 4)); // Displays 'Mozilla' console.log(anyString.substring(0, 7)); console.log(anyString.substring(0, 10));
substring()
with length
propertyThe following example uses the substring()
method and {{jsxref("String.length", "length")}} property to extract the last characters of a particular string. This method may be easier to remember, given that you don't need to know the starting and ending indices as you would in the above examples.
// Displays 'illa' the last 4 characters var anyString = 'Mozilla'; var anyString4 = anyString.substring(anyString.length - 4); console.log(anyString4); // Displays 'zilla' the last 5 characters var anyString = 'Mozilla'; var anyString5 = anyString.substring(anyString.length - 5); console.log(anyString5);
substring()
and substr()
There's a subtle difference between the substring()
and {{jsxref("String.substr", "substr()")}} methods, so you should be careful not to get them confused.
The arguments of substring()
represent the starting and ending indexes, while the arguments of substr()
represent the starting index and the number of characters to include in the returned string.
var text = 'Mozilla'; console.log(text.substring(2,5)); // => "zil" console.log(text.substr(2,3)); // => "zil"
substring()
and slice()
The substring()
and {{jsxref("String.slice", "slice()")}} methods are almost identical, but there are a couple of subtle differences between the two, especially in the way negative arguments are dealt with.
The substring()
method swaps its two arguments if indexStart
is greater than indexEnd
, meaning that a string is still returned. The {{jsxref("String.slice", "slice()")}} method returns an empty string if this is the case.
var text = 'Mozilla'; console.log(text.substring(5, 2)); // => "zil" console.log(text.slice(5, 2)); // => ""
If either or both of the arguments are negative or NaN
, the substring()
method treats them as if they were 0
.
console.log(text.substring(-5, 2)); // => "Mo" console.log(text.substring(-5, -2)); // => ""
slice()
also treats NaN
arguments as 0
, but when it is given negative values it counts backwards from the end of the string to find the indexes.
console.log(text.slice(-5, 2)); // => "" console.log(text.slice(-5, -2)); // => "zil"
See the {{jsxref("String.slice", "slice()")}} page for more examples with negative numbers.
The following example replaces a substring within a string. It will replace both individual characters and substrings. The function call at the end of the example changes the string Brave New World
to Brave New Web
.
// Replaces oldS with newS in the string fullS function replaceString(oldS, newS, fullS) { for (var i = 0; i < fullS.length; ++i) { if (fullS.substring(i, i + oldS.length) == oldS) { fullS = fullS.substring(0, i) + newS + fullS.substring(i + oldS.length, fullS.length); } } return fullS; } replaceString('World', 'Web', 'Brave New World');
Note that this can result in an infinite loop if oldS
is itself a substring of newS
— for example, if you attempted to replace 'World' with 'OtherWorld' here. A better method for replacing strings is as follows:
function replaceString(oldS, newS, fullS) { return fullS.split(oldS).join(newS); }
The code above serves as an example for substring operations. If you need to replace substrings, most of the time you will want to use {{jsxref("String.prototype.replace()")}}.
Specification | Status | Comment |
---|---|---|
{{SpecName('ESDraft', '#sec-string.prototype.substring', 'String.prototype.substring')}} | {{Spec2('ESDraft')}} | |
{{SpecName('ES6', '#sec-string.prototype.substring', 'String.prototype.substring')}} | {{Spec2('ES6')}} | |
{{SpecName('ES5.1', '#sec-15.5.4.15', 'String.prototype.substring')}} | {{Spec2('ES5.1')}} | |
{{SpecName('ES1')}} | {{Spec2('ES1')}} | Implemented in JavaScript 1.0. |
The compatibility table in this page is generated from structured data. If you'd like to contribute to the data, please check out https://github.com/mdn/browser-compat-data and send us a pull request.
{{Compat("javascript.builtins.String.substring")}}