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authorDevJo <sa02045@naver.com>2021-12-13 19:50:12 +0900
committerKyle <mkitigy@gmail.com>2021-12-27 07:55:15 +0900
commitc581ac7c5b0ba9552a0e34f467c4f62050e0c455 (patch)
tree19b19a6799f4363e601ab6b24a009701e3dc186c /files/ko/web/javascript/reference/global_objects/math
parent06bc06d023186d8d36f90c88e76a9e4c03446534 (diff)
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remove: notranslate in web/javascript/reference/global_objects
Diffstat (limited to 'files/ko/web/javascript/reference/global_objects/math')
-rw-r--r--files/ko/web/javascript/reference/global_objects/math/max/index.html6
1 files changed, 3 insertions, 3 deletions
diff --git a/files/ko/web/javascript/reference/global_objects/math/max/index.html b/files/ko/web/javascript/reference/global_objects/math/max/index.html
index a70a5bf744..439aebe905 100644
--- a/files/ko/web/javascript/reference/global_objects/math/max/index.html
+++ b/files/ko/web/javascript/reference/global_objects/math/max/index.html
@@ -55,7 +55,7 @@ browser-compat: javascript.builtins.Math.max
<h3 id="Using_Math.max"><code>Math.max()함수 사용하기</code></h3>
-<pre class="brush: js notranslate">Math.max(10, 20); // 20
+<pre class="brush: js">Math.max(10, 20); // 20
Math.max(-10, -20); // -10
Math.max(-10, 20); // 20
</pre>
@@ -77,7 +77,7 @@ var max = arr.reduce(function(a, b) {
<code>Math.max(1, 2, 3)</code>와 동일하지만 프로그래밍 방식으로 생성 된 모든 크기의 배열에서 <code>getMaxOfArray()</code>를 사용할 수 있습니다.
</p>
-<pre class="brush: js notranslate">function getMaxOfArray(numArray) {
+<pre class="brush: js">function getMaxOfArray(numArray) {
return Math.max.apply(null, numArray);
}
</pre>
@@ -92,7 +92,7 @@ var max = arr.reduce(function(a, b) {
<p>또한 {{jsxref("Operators/Spread_syntax", "spread operator")}}이 함수를 사용하면 배열의 숫자들 중 가장 큰 숫자를 쉽게 얻을 수 있습니다.</p>
-<pre class="brush: js notranslate">var arr = [1, 2, 3];
+<pre class="brush: js">var arr = [1, 2, 3];
var max = Math.max(...arr);
</pre>