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| author | Florian Merz <me@fiji-flo.de> | 2021-02-11 14:50:24 +0100 |
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| committer | Florian Merz <me@fiji-flo.de> | 2021-02-11 14:50:24 +0100 |
| commit | 2c2df5ea01eb5cd8b9ea226b2869337e59c5fe3e (patch) | |
| tree | 86ab4534d10092b293d4b7ab169fe1a8a2421bfa /files/pt-pt/web/mathml/examples/mathml_pythagorean_theorem | |
| parent | 8260a606c143e6b55a467edf017a56bdcd6cba7e (diff) | |
| download | translated-content-2c2df5ea01eb5cd8b9ea226b2869337e59c5fe3e.tar.gz translated-content-2c2df5ea01eb5cd8b9ea226b2869337e59c5fe3e.tar.bz2 translated-content-2c2df5ea01eb5cd8b9ea226b2869337e59c5fe3e.zip | |
unslug pt-pt: move
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| -rw-r--r-- | files/pt-pt/web/mathml/examples/mathml_pythagorean_theorem/index.html | 19 |
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diff --git a/files/pt-pt/web/mathml/examples/mathml_pythagorean_theorem/index.html b/files/pt-pt/web/mathml/examples/mathml_pythagorean_theorem/index.html new file mode 100644 index 0000000000..d4edbfc4dd --- /dev/null +++ b/files/pt-pt/web/mathml/examples/mathml_pythagorean_theorem/index.html @@ -0,0 +1,19 @@ +--- +title: Provar o teorema de Pitágoras +slug: Web/MathML/Examples/MathML_teorema_de_Pitagoras +tags: + - Beginner + - Educação de matemática + - Exemplo + - Guía + - Matemática HTML5 + - MathML +translation_of: Web/MathML/Examples/MathML_Pythagorean_Theorem +--- +<p>Iremos provar o teorema de Pitágoras:</p> + +<p><strong>Declaração:</strong> Num triângulo retângulo, o quadrado da hipotenusa é igual à soma dos quadrados dos outros dois lados.</p> + +<p>Isto é, se <strong>a</strong> e <strong>b</strong> são os catetos, e <strong>c</strong> é a hipotenusa então<math><mrow><msup><mi> a </mi><mn>2</mn></msup> <mo> + </mo> <msup><mi> b </mi><mn>2</mn></msup> <mo> = </mo> <msup><mi> c </mi><mn>2</mn></msup> </mrow> </math>.</p> + +<p><strong>Prova:</strong> Podemos provar o teorema algebricamente mostrando que a área do quadrado grande é igual à área do quadrado interior (hipotenusa ao quadrado) mais a área dos quatro triângulos:<math style="display: block;"><mtable columnalign="right center left"><mtr><mtd><msup><mrow><mo>( </mo> <mi> a </mi> <mo> + </mo> <mi> b </mi> <mo> ) </mo> </mrow> <mn> 2 </mn> </msup> </mtd> <mtd> <mo> = </mo> </mtd> <mtd> <msup><mi> c </mi><mn>2</mn></msup> <mo> + </mo> <mn> 4 </mn> <mo> ⋅ </mo> <mo>(</mo> <mfrac> <mn> 1 </mn> <mn> 2 </mn> </mfrac> <mi> a </mi><mi> b </mi> <mo>)</mo> </mtd> </mtr> <mtr> <mtd> <msup><mi> a </mi><mn>2</mn></msup> <mo> + </mo> <mn> 2 </mn><mi> a </mi><mi> b </mi> <mo> + </mo> <msup><mi> b </mi><mn>2</mn></msup> </mtd> <mtd> <mo> = </mo> </mtd> <mtd> <msup><mi> c </mi><mn>2</mn></msup> <mo> + </mo> <mn> 2 </mn><mi> a </mi><mi> b</mi></mtd></mtr><mtr><mtd></mtd></mtr><mtr><mtd><msup><mi>a </mi><mn>2</mn></msup> <mo> + </mo> <msup><mi> b </mi><mn>2</mn></msup> </mtd> <mtd> <mo> = </mo> </mtd> <mtd> <msup><mi> c </mi><mn>2</mn></msup> </mtd> </mtr> </mtable> </math></p> |